如何能快速取得所有字段的字段名?急用!请各位帮帮忙!

如何能快速取得所有字段的字段名?急用!请各位帮帮忙!
[26 byte] By [mjh7781-mjh] at [2008-5-26]
# 1
select * from table_name where 1=2
olili-美露 at 2007-10-24 > top of Msdn China Tech,PowerBuilder,基础类...
# 2
上面的语句在sybase ISQL里可快速显示所有字段名

另可从sybase的一系统表里可找出(具体我也记不清了,查help即可)
olili-美露 at 2007-10-24 > top of Msdn China Tech,PowerBuilder,基础类...
# 3
在哪儿取得?数窗里还是 SQL 语句里?
sincerity-sincerity at 2007-10-24 > top of Msdn China Tech,PowerBuilder,基础类...
# 4
是在数窗里!!
mjh7781-mjh at 2007-10-24 > top of Msdn China Tech,PowerBuilder,基础类...
# 5
long ll_i, ll_count

ll_count = long(dwname.Describe("DataWindow.Column.Count")
for ll_i = 1 to ll_count
MessageBox("",dwname.Descirbe("#" + string(ll_i) + ".Name"))
next
sincerity-sincerity at 2007-10-24 > top of Msdn China Tech,PowerBuilder,基础类...
# 6
看看!学习!我有例程啊!
ideage-莲花宝典 at 2007-10-24 > top of Msdn China Tech,PowerBuilder,基础类...
# 7
用数据库的系统表来作。
或者用pb的系统表
heliang-流浪的风筝 at 2007-10-24 > top of Msdn China Tech,PowerBuilder,基础类...