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取出表中一字段的头一个字符与所给字符相同的记录,这条sql语句怎么写?

取出表中一字段的头一个字符与所给字符相同的记录,这条sql语句怎么写?

[2 byte] By [uml] at [2007-12-12]

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# 1

select .. from .. where substr(zd,1,1)=:zd;

jiazhij-雨中漫步 at 2007-10-24 >

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# 2

忘了说了，是在数据窗口中，通过retrieve("字符")检索记录

uml at 2007-10-24 >

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